PSTET Answer Key 2020 Punjab TET Solutions Paper 1 and 2

PSTET Answer Key 2020 for the Punjab State Teacher Eligibility Test held on 19 Jan 2020. Check Expected Cut Off Marks for the Punjab TET Paper 1 and Paper 2

State Council of Educational Research & Training (SCERT), Punjab has successfully conducted the Punjab TET Test. Now the department will soon release the PSTET Answer Key 2020 for Paper 1 and Paper 2. This test was held on 19.01.2020 across various exam centers across Punjab.

The Question Paper Solutions can be downloaded for the following papers:

PSTET Paper 1Child Development and Pedagogy3030
Language 13030
Language 23030
Environmental studies3030
PSTET Paper 2Child Development and Pedagogy3030
Language 13030
Language 23030
Maths or Science6060
Social Science6060

Punjab TET PSTET Answer Key 19 Jan 2020

The Official Response Sheet of Punjab TET Exam will be available online at the official website Applicants can use it to check their marks for Paper 1 and Paper 2.

Candidates can also raise objections to the official answer key of the PSTET exam in case they do not seem to agree with the answers suggested in it. Objections can be raised within 5 days from the date of release of Answer Key.

  • Department Name: State Council of Educational Research & Training
  • Date of Exam: 19 Jan 2020
  • Paper 1 Timings: 10:00 AM to 12:30 PM
  • Paper 2 Timings: 2:30 PM to 5:00 PM
  • Category: Punjab PSTET Answer Key 2020
  • Official Website:

The PSTET 2020 Cut Off Marks depend on the various factors like difficulty level of test, the number of applicants appeared, marks scored by candidates, etc. 

The minimum marks of cut-off will be 60% of total marks i.e. 90 marks out 150 marks. State board can decide concession for some categories of candidates in the minimum cut-off marks

Below is the formula to calculate the total marks.

Total Marks Scores = (1 x No. of Right Answers)

Candidates must follow the marking scheme while using the official answer key. Candidates have to score marks more than or equal to 60% of the total marks of the exam.

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Updated: January 17, 2020 — 10:11 AM

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